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3x^2-45x=-45
We move all terms to the left:
3x^2-45x-(-45)=0
We add all the numbers together, and all the variables
3x^2-45x+45=0
a = 3; b = -45; c = +45;
Δ = b2-4ac
Δ = -452-4·3·45
Δ = 1485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1485}=\sqrt{9*165}=\sqrt{9}*\sqrt{165}=3\sqrt{165}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-3\sqrt{165}}{2*3}=\frac{45-3\sqrt{165}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+3\sqrt{165}}{2*3}=\frac{45+3\sqrt{165}}{6} $
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